Time Before

Time before a city gets upsold to that was ideally how reality would play out.

Time before a supercomputer has its switch turned on gets upsold to that was ideally how reality would play out.

Shiny Blue Marble in the Past likely said Lightning is in the sky, it is not able to be captured and put in a glass jar

A supercomputer, A new supercomputer likely to be turned on in 2040? Yes

More likely Now that I said that? Yes

World before that Supercomputer in 2040 existed, World after that Supercomputer likely to be new and changed in Profound ways I cannot currently fully comprehend. I believe it is likely to rely upon electricity, thus I provide starting preparation to help with the Power Efficiency of that 2040 Supercomputer.

Little changes upfront? Documentable? Power in that

160 years of Civil Rights has failed to Amplify Ideally for Diversity and Minorities in the South of United States of America? Yes. A many year head start for that supercomputer could be a lot of help? Yes

Resistance over distance has potential for Energy Loss

Interesting Increasing Resistance can lead to lower Current, if Current is kept constant, then Increased Resistance would likely increase heat

What variables are held constant in the system factors into perceptions of increases. Point of Reference not something always considered in Electrical Circuits?

P=I^2*R

thus if current through a 1 kiloohms wire leads to a specific power loss

P=I^2 * 1 kiloohms = I^2 kilohms

if I set the current to constant, say 1 kiloamp

P = 1 kiloamp squared kiloohms = 1 (some-prefix)watt

if I were to double the resistance to 2 kiloohms

Power Throughput would be?

P = 2 kiloamp squared kiloohms = 2 (some-prefix) watt

1000 AMP * 1000 Ohms = 1,000,000 Watts = 1 MW

So if I had wire that over a distance 5 kilometers created 1 kiloohm, doubling the distance of that wire 10 kilometers could lead to double the power loss if I kept current constant

Same power with double the resistance?

P=I^2
P=I^2*2

i^2=2(i^2)

0 = 2i^2-i^2 = i^2

i^2 = 0, i = 0? must have something wrong

current doesn’t maintain a constant value between those two equations

P=i1^2*(1 kOhm)
P=i2^2*(2 kOhm)

Set power to 1,000,000 W, 1 MW

1,000,000= i1^2

1,000,000 = 2i2^2

500,000 = i2^2

i2 = sqrt(500,000) = 707.12 A

i1 = sqrt(1,000,000) = 1000 A

i1 = 1 kA
i2 with double length of wire = 707.12 A

Voltage1 vs Voltage2?

P = VI

1 MW held constant

1 MW = V1*1 kiloamps

V1 = 1,000,000 W / 1000 A = 1000V = 1 kV

1 MW= V2*707.12 A

1 MW= V2*0.70712 kiloamps

V2 = 1,000,000 W / 707.12 A = 1414.19 V = 1.4 kV

Keeping Power constant increased resistance equals less amps

Less amps at same Power Output Requires Higher Voltages

Greater volts required for delivering same power over a longer distance assuming resistance per foot of wire remains constant

Using the numbers from this example (that are not real) distance of 5 kilometers equals 1 kV will deliver 1 megawatt. Increasing distance to 10 kilometers (double the distance) will require 1.4 kV to deliver the same 1 megawatt.

Proximity factors into Power Efficiency.

Keep 1 kV constant then doubling length of wire?

P = VI = i2 kV

P = i2^2 * (2 kiloohms)

i2 kV = i2^2 * (2 kiloohms)

1 kV / 2 kiloohms = (i2*i2)/i2

i2 = 1000 V / 2000 Ohms = 0.5 kA

P2 at 1000V constant would be = 1 kv(0.5kA) = 1000 V*500A = 500,000 A = 0.5 MW

Potential for resistive properties to act in different ways dependent on current temperature and state?

Does a wire have more resistance on a wire close to absolute zero or close to melting point of the wire?

Oscilloscope Output with a Torch Under the wire on a circuit?